Vlastimil Brom wrote:
2009/9/15 Ulrich Eckhardt <eckha...@satorlaser.com>:
Hi!
"'abc'.split('')" gives me a "ValueError: empty separator".
However, "''.join(['a', 'b', 'c'])" gives me "'abc'".
Why this asymmetry? I was under the impression that the two would be
complementary.
Uli
maybe it isn't quite obvious, what the behaviour in this case should be;
re.split also works with empty delimiter (and returns the original string)
re.split("", "abcde")
['abcde']
If you need to split the string into the list of single characters
like in your example, list() is the possible way:
list("abcde")
['a', 'b', 'c', 'd', 'e']
I'd prefer it to split into characters. As for re.split, there are times
when it would be nice to be able to split on a zero-width match such as
r"\b" (word boundary).
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