Bruno Desthuilliers wrote:
(snip)
Joel Juvenal Rivera Rivera wrote:
Hi i was playing around with my code the i realize of this
###################
_uno__a = 1
class uno():
__a = 2
def __init__(self):
print __a
uno()
###################
and prints 1
<snip>
I beg to disagree. The problem (well... what I think is a problem,
actually) IS that name mangling is applied to a method *local* variable.
It is not a local variable, because there's no assignment within that
same method. That decision happens at compile time of the definition.
Once it's not a local, then it needs to get mangled, per the rules for
double-underscore.
Try adding a __a = 49 before or after the line in question. Either
one will change the behavior (and/or the error message) to indicate that
it's a local.
DaveA
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