Kitlbast wrote:
On Oct 7, 3:04 am, Raymond Hettinger <pyt...@rcn.com> wrote:
On Oct 6, 4:06 pm, Kitlbast <vlad.shevche...@gmail.com> wrote:
Hi there,
the code below on Python 2.5.2:
from itertools import groupby
info_list =
{'profile': 'http://somesite.com/profile1', 'account': 61L},
{'profile': 'http://somesite.com/profile2', 'account': 64L},
{'profile': 'http://somesite.com/profile3', 'account': 61L},
]
grouped_by_account =roupby(info_list, lambda x: x['account'])
for acc, iter_info_items in grouped_by_account:
print 'grouped acc: ', acc
gives output:
grouped acc: 61
grouped acc: 64
grouped acc: 61
am I doing something wrong?
Try another variant of groupby() that doesn't require the data to be
sorted:
http://code.activestate.com/recipes/259173/
Raymond
I've checked few options of groupby() implementations
1. def groupby(_list, key_func):
res =}
for i in _list:
k =ey_func(i)
if k not in res:
res[k] =i]
else:
res[k].append(i)
return res
2. def groupby(_list, key_func):
res =}
[res.setdefault(key_func(i), []).append(i) for i in _list]
return res
second one with setdefault works little bit slower then (1), although
it use list comprehension
Or option 3: use defaultdict
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