import re
line='2009-11-22 12:15:441 lmqkjsfmlqshvquhsudfhqf qlsfh qsduidfhqlsiufh
qlsiuf qldsfhqlsifhqlius dfh warning qlsfj lqshf lqsuhf lqksjfhqisudfh qiusdfhq
iusfh'
re.match('.*(?!warning)',line)
<_sre.SRE_Match object at 0xb75b1598>
I would expect that this would NOT match as it's a negative lookahead and
warning is in the string.
This first finds everything (".*") and then asserts that
"warning" doesn't follow it, which is correct in your example.
You may have to assert that "warning" doesn't exist at every
point along the way:
re.match(r'(?:(?!warning).)*',line)
which will match up-to-but-not-including the "warning" text. If
you don't want it at all, you'd have to also anchor the far end
re.match(r'^(?:(?!warning).)*$',line)
but in the 2nd case I'd just as soon invert the test:
if 'warning' not in line:
do_stuff()
-tkc
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