On Mon, Nov 30, 2009 at 10:54 AM, Benjamin Kaplan <benjamin.kap...@case.edu> wrote: > > I don't know if anyone considers python's incomplete implementation of > closures a "feature" but it's documented so it's not really a bug > either. I believe there is a trick with default arguments to get this > to work, but I don't use lambdas enough to remember it. > -- > http://mail.python.org/mailman/listinfo/python-list >
Well default arguments isn't the only way - and *sometimes* it's not workable. Another way to make closures in Python is to define the function a within function b which returns function a and in your loop call function b. i guess if you wanted to do that purely with lambas (outside of using default arguments like i=i) you'd have to do something like a = [] for x in xrange(10): a.append((lambda x: lambda: x)(x)) never tried that though.. -- http://mail.python.org/mailman/listinfo/python-list
