On Dec 11, 9:26 am, Jan Mach <jan.m...@cesnet.cz> wrote: > Hi everybody, > I am currently solving the following problem and I am stuck. I am trying > to create instance of the class of variable name. I know, that the > following works: > > if (something): > classToUse = C1 > else: > classToUse = C2 > > o = classToUse() > > ,but this is not what I want. I need to have the class name in the string and > then > instantiate it: > > (this does not work of course) > classToUse = "C1" > o = classToUse() > > It is because I don`t know at the moment what the name of the class will be, > I will > load it from the file or pass it as argument. Does anyone know what is the > correct syntax > to accomplish this? > > Thanks for your time in advance > > Jan Mach > > smime.p7s > 4KViewDownload
You can always do eval(my_string) to get the class object. Better I think is to make an explicit dictionary of options (much safer). classes = dict((cls.__name__, cls) for cls in (C1, C2)) classes["C1"] # gives you C1 classes["C2"] # gives you C2 Richard. -- http://mail.python.org/mailman/listinfo/python-list
