On Dec 11, 10:30 am, Mark Dickinson <dicki...@gmail.com> wrote: > > It looks like an infinite series with term `t`, where`n` = (2k-1)^2 > > and `d` = d = 4k(4k+2) for k = 1... Does it have a name? > > Interesting. So the general term here is > 3 * (2k choose k) / (16**k * (2*k+1)), k >= 0. > > I've no idea what its name is or where it comes from, though. I > expect Raymond Hettinger would know.
After a cup of coffee, it's much clearer: this just comes from the Taylor series for arcsin(x), applied to x = 1/2 to get asin(1/2) = pi/ 6. -- Mark -- http://mail.python.org/mailman/listinfo/python-list
