--- On Wed, 12/16/09, Peter Otten <[email protected]> wrote:
> Another possibility:
>
> >>> print re.sub('abc', lambda m: r'a\nb\n.c\a',
> '123abcdefg')
> 123a\nb\n.c\adefg
I'm not sure whether that is clever, ugly, or just plain strange!
I think I'll stick with:
>>> m = re.match('^(.*)abc(.*)$', '123abcdefg')
>>> print m.group(1) + r'a\nb\n.c\a' + m.group(2)
123a\nb\n.c\adefg
It's much less likely to fry the poor maintenance programmer's mind.
-EdK
Ed Keith
[email protected]
Blog: edkeith.blogspot.com
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