Dan, >> Unfortunately, Windows is not a respectable OS. Unlike Unix, it allows >> two processes to bind to the same port. The theory is that this somehow >> allows the two processes to share their workload. One thing the OP can >> portably do, is try to connect() to the port. If that succeeds, then a >> server program is already running at that port, so he should exit.
> Beware of the converse, though. If a process *cannot* connect to the > port, then it should *not* assume that another server *isn't* running. > If two potential servers both start at the same time, and each tries to > connect, then both will fail, but you don't want both to start, either. Thank you for pointing out that nuance. Best regards, Malcolm -- http://mail.python.org/mailman/listinfo/python-list
