You're right. Y. Works fine. The produces datetime.datetime(2009, 1, 2,
13, 1, 15).
If I now use
t2=datetime.datetime.strptime("2009/01/04 13:01:15","%Y/%m/%d %H:%M:%S")
I get tw as
datetime.datetime(2009, 1, 4, 13, 1, 15)
Then t2-t1 gives,
datetime.timedelta(2)
which is a 2 day difference--I guess. Strange.
Changing
t2=datetime.datetime.strptime("2009/01/04 14:00:30","%Y/%m/%d %H:%M:%S")
and differencing gives me,
datetime.timedelta(2, 3555), which seems to indicate a 2 day and 3555
second difference. Interesting, but I think there must be another way to
do this. Maybe not.
Roy Smith wrote:
In article <hh9dmv$f9...@news.eternal-september.org>,
"W. eWatson" <wolftra...@invalid.com> wrote:
t1=datetime.datetime.strptime("2009/01/02 13:01:15","%y/%m/%d %H:%M:%S")
doesn't do it.
ValueError: time data did not match format: data=2009/01/02 13:01:15
fmt=%y/%m/%d %H:%M:%S
The first thing that jumps out at me is that %y is the two-digit year. You
want %Y for 4-digit year.
One thing to keep in mind is that "2009/01/02 13:01:15" is ambiguous
without a time zone. Even if you assume that both timestamps were from the
same location, you need to know what daylight savings rules that location
uses, to do this right.
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