On Jan 18, 6:52 am, "kak...@gmail.com" <kak...@gmail.com> wrote: > Hello to all! > I want to parse a log file with the following format for > example: > TIMESTAMPE Operation FileName > Bytes > 12/Jan/2010:16:04:59 +0200 EXISTS sample3.3gp 37151 > 12/Jan/2010:16:04:59 +0200 EXISTS sample3.3gp 37151 > 12/Jan/2010:16:04:59 +0200 EXISTS sample3.3gp 37151 > 12/Jan/2010:16:04:59 +0200 EXISTS sample3.3gp 37151 > 12/Jan/2010:16:04:59 +0200 EXISTS sample3.3gp 37151 > 12/Jan/2010:16:05:05 +0200 DELETE sample3.3gp 37151 > > How can i count the operations for a month(e.g total of 40 Operations, > 30 exists, 10 delete?) > Any tips? > > Thanks in advance > Antonis
time.strptime(string[, format]) Parse a string representing a time according to a format. The return value is a struct_time as returned by gmtime() or localtime(). The format parameter uses the same directives as those used by strftime (); it defaults to "%a %b %d %H:%M:%S %Y" which matches the formatting returned by ctime(). If string cannot be parsed according to format, or if it has excess data after parsing, ValueError is raised. The default values used to fill in any missing data when more accurate values cannot be inferred are (1900, 1, 1, 0, 0, 0, 0, 1, -1). >>> import time >>> ts='12/Jan/2010:16:04:59 +0200' >>> time.strptime(ts[:-6], '%d/%b/%Y:%H:%M:%S') time.struct_time(tm_year=2010, tm_mon=1, tm_mday=12, tm_hour=16, tm_min=4, tm_sec=59, tm_wday=1, tm_yday=12, tm_isdst=-1) I leave the conversion of the last six characters (the time zone offset) as an exercise for the student. :) -- http://mail.python.org/mailman/listinfo/python-list
