Jean-Michel Pichavant wrote:
Gilles Ganault wrote:
Hello
I use a dictionary to keep a list of users connected to a web site.
To avoid users from creating login names that start with digits in
order to be listed at the top, I'd like to sort the list differently
every minute so that it'll start with the next letter, eg. display the
list from A...Zdigits the first time, then B...ZAdigits, etc.
That way, users have no incentive to create login names that start
with either a digit or letter A.
I see that dictionaries can be sorted using the... sort() method, but
is it possible to have Python start sorting from a different letter?
Thank you.
Here is one possible solution
l = ['1a', 'a', 'b','c','av','ac'] # you mentioned a dictionary in
your post, if so, l = myDict.keys()
l.sort() # sort your list once and for all
for start in '1abcd':
result = [name for name in l if name[0] >= start] + [name for name
in l if name[0] < start]
print result
['1a', 'a', 'b', 'c', 'av', 'ac']
['a', 'b', 'c', 'av', 'ac', '1a']
['b', 'c', '1a', 'a', 'av', 'ac']
['c', '1a', 'a', 'b', 'av', 'ac']
['1a', 'a', 'b', 'c', 'av', 'ac']
Jean-Michel
Sorry, the code I provided produce this output:
['1a', 'a', 'ac', 'av', 'b', 'c']
['a', 'ac', 'av', 'b', 'c', '1a']
['b', 'c', '1a', 'a', 'ac', 'av']
['c', '1a', 'a', 'ac', 'av', 'b']
['1a', 'a', 'ac', 'av', 'b', 'c']
which is actually what you are searching for. I just messed up with my
ipython shell history :o)
JM
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