Olof Bjarnason wrote:
2010/2/10 Peter Otten <__pete...@web.de>:
pyt...@bdurham.com wrote:
Does Python provide a way to format a string according to a
'picture' format?
For example, if I have a string '123456789' and want it formatted
like '(123)-45-(678)[9]', is there a module or function that will
allow me to do this or do I need to code this type of
transformation myself?
A basic implementation without regular expressions:
def picture(s, pic, placeholder="@"):
... parts = pic.split(placeholder)
... result = [None]*(len(parts)+len(s))
... result[::2] = parts
... result[1::2] = s
... return "".join(result)
...
picture("123456789", "(@@@)-@@-(@@@)[...@]")
'(123)-45-(678)[9]'
Peter
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Inspired by your answer here's another version:
def picture(s, pic):
... if len(s)==0: return pic
... if pic[0]=='#': return s[0]+picture(s[1:], pic[1:])
... return pic[0]+picture(s, pic[1:])
...
picture("123456789", "(###)-##-(###)[#]")
'(123)-45-(678)[9]'
Here's a version without recursion:
>>> def picture(s, pic):
... pic = pic.replace("%", "%%").replace("#", "%s")
... return pic % tuple(s)
...
>>> picture("123456789", "(###)-##-(###)[#]")
'(123)-45-(678)[9]'
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