You may also want to look into mechanize module. On Thu, Mar 4, 2010 at 6:11 PM, Michael Rudolf <spamfres...@ch3ka.de> wrote:
> Am 04.03.2010 11:38, schrieb Karen Wang: > > Hi all, >> >> I want to use python to access to https server, like >> "https://212.218.229.10/chinatest/"; >> >> If open it from IE, will see the pop-up login windows like this >> >> >> >> I tried several ways but always only get page for" HTTP Error 401.2 - >> Unauthorized" error. ( myusername and mypassword are all correct) >> >> Below is my code: >> >> import urllib2 >> >> values = { >> >> 'user' : "myusername", >> >> "pass' : "mypassword" } >> >> data = urllib2.urlencode(values) >> >> t = urllib2.urlopen('https://212.218.229.10/chinatest/',data) >> >> print t.read() >> >> where I am wrong ? >> > > AFAIR does urlopen() expect the password to be Base64-encoded, not > urlencoded. > > You might also need to add an AUTH-Line. But this all does not matter, as > there is more than one AUTH-Method you'd have to implement them all, but > fortunately urllib2.HTTPBasicAuthHandler and urllib2.HTTPBasicAuthHandler > exist. > > So use them: > > import urllib2 > passman = urllib2.HTTPPasswordMgrWithDefaultRealm() > passman.add_password(None, theurl, username, password) > authhandler = urllib2.HTTPBasicAuthHandler(passman) > opener = urllib2.build_opener(authhandler) > urllib2.install_opener(opener) > pagehandle = urllib2.urlopen(theurl) > > (taken from > http://www.voidspace.org.uk/python/articles/authentication.shtml ) > > Further reference: > http://www.python.org/doc/2.5.2/lib/module-urllib2.html > http://www.python.org/doc/2.5.2/lib/urllib2-examples.html > > HTH, > Michael > -- > http://mail.python.org/mailman/listinfo/python-list >
-- http://mail.python.org/mailman/listinfo/python-list
