Kushal Kumaran <kushal.kumaran+pyt...@gmail.com> writes: > On Thu, Apr 8, 2010 at 7:39 PM, jorma kala <jjk...@gmail.com> wrote: >> Hi, >> >> I'd like to call an external application (firefox) from a python program (a >> PyQT GUI), but I want the external application to run in the background, I >> mean I do not want my python calling program to wait till the external >> subprocess terminates. >> I've tried this: >> >> call(["firefox", "http://www.python.org";]) >> >> but my PyQT interface freezes until I terminate Firefox. >> Is there any parameter I need to use with call so that the python calling >> program doesn't wait for the termination of the subprocess? >> > > Use subprocess.Popen instead of directly using subprocess.call.
Or (maybe) better, use the webbrowser module. http://docs.python.org/release/2.5.2/lib/module-webbrowser.html -- John Bokma j3b Hacking & Hiking in Mexico - http://johnbokma.com/ http://castleamber.com/ - Perl & Python Development -- http://mail.python.org/mailman/listinfo/python-list
