I think you are better off not binding a button like you are doing. Use the "command" option to get the behavior you want. E.g:
class MyApp: def __init__(self, parent): self.myParent = parent self.myContainer1 = Frame(parent) self.myContainer1.pack() self.entry = Entry(self.myContainer1) self.entry.grid(row=0,column=0, columnspan=2) self.button1 = Button(self.myContainer1, command=(lambda: self.button1Click(self))) self.button1.configure(text="...") self.button1.grid(row=0, column=2) self.button1.bind("<Return>", self.button1Click) def button1Click(self, event): filePick = tkFileDialog.askopenfilename() James On Thursday 12 May 2005 03:43 pm, [EMAIL PROTECTED] wrote: > I am creating a very simple GUI with one Entry widget and > one Button. The purpose of the Button widget is to Browse for > a file using tkFileDialog.askopenfilename(). > > I bind the button to a handler which spawns a tkFileDialog. This > works but the button __stays depressed__ after the handler returns! > Any ideas why? > > class MyApp: > def __init__(self, parent): > self.myParent = parent > self.myContainer1 = Frame(parent) > self.myContainer1.pack() > > self.entry = Entry(self.myContainer1) > self.entry.grid(row=0,column=0 columnspan=2) > > self.button1 = Button(self.myContainer1) > self.button1.configure(text="...") > self.button1.grid(row=0, column=2) > self.button1.bind("<Button-1>", self.button1Click) > self.button1.bind("<Return>", self.button1Click) > > > def button1Click(self, event): > filePick = tkFileDialog.askopenfilename() -- James Stroud UCLA-DOE Institute for Genomics and Proteomics Box 951570 Los Angeles, CA 90095 http://www.jamesstroud.com/ -- http://mail.python.org/mailman/listinfo/python-list