Have I missed something, or wouldn't this work just as well: >>> list_of_strings = ['2', 'awes', '3465sdg', 'dbsdf', 'asdgas'] >>> [word for word in list_of_strings if word[0] == 'a'] ['awes', 'asdgas']
Cheers, Xav On Mon, May 10, 2010 at 6:40 PM, Jimbo <nill...@yahoo.com> wrote: > Hello > > I am trying to find if there is a string OR list function that will > search a list of strings for all the strings that start with 'a' & > return a new list containing all the strings that started with 'a'. > > I have had a search of Python site & I could not find what I am > looking for, does a function like this exist? > > The only one that I think could work is, use the string > function .count() > > algorithm: to exract all the words inside a list that start with 'a' > - make sure the list is arranged in alphabetical order > - convert the list to a big string > - use list_string.count(',a') to obtain the index where the last 'a' > word occurs > - convert back into string (yes this is a REAL hack :P) > - and then create a new list, ie, new_list = list[0:32] > - & return new_list > > Ok that algorithm is terrible, I know, & I just realise that it wont > work for letters after 'a'. So if anyone could suggest a function or > algorithm it would be extremely helpful > -- > http://mail.python.org/mailman/listinfo/python-list >
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