Peter Hansen wrote: > > Or just use the .timetuple() method on datetime objects and sort on the > 8th element of the 9-element tuple, which is the day-of-the-year.
An interesting idea. But wouldn't sorting by (dd.month,dd.day) be more effective? In other words: Does .timetuple() create a tuple, or does it just return a tuple which is present anyway? Greets, -- Volker Grabsch ---<<(())>>--- \frac{\left|\vartheta_0\times\{\ell,\kappa\in\Re\}\right|}{\sqrt [G]{-\Gamma(\alpha)\cdot\mathcal{B}^{\left[\oint\!c_\hbar\right]}}} -- http://mail.python.org/mailman/listinfo/python-list