On Thursday 01 July 2010 16:50:59 Lawrence D'Oliveiro wrote:
> Nevertheless, it it at least self-consistent. To return to my original
> macro:
>
> #define Descr(v) &v, sizeof v
>
> As written, this works whatever the type of v: array, struct, whatever.
>
Doesn't seem to, sorry. Using Michael Torrie's code example, slightly
modified...
[r...@tigris ~]$ cat example.c
#include <stdio.h>
#define Descr(v) &v, sizeof v
int main(int argc, char ** argv)
{
char *buf = malloc(512 * sizeof(char));
const int a = 2, b = 3;
snprintf(Descr(buf), "%d + %d = %d\n", a, b, a + b);
fprintf(stdout, buf);
free(buf);
return 0;
} /*main*/
[r...@tigris ~]$ clang example.c
example.c:11:18: warning: incompatible pointer types passing 'char **',
expected
'char *' [-pedantic]
snprintf(Descr(buf), "%d + %d = %d\n", a, b, a + b);
^~~~~~~~~~
example.c:4:18: note: instantiated from:
#define Descr(v) &v, sizeof v
^~~~~~~~~~~~
<<snip>>
[r...@tigris ~]$ ./a.out
Segmentation fault
----
Rami Chowdhury
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-- Benford's Law of Controversy
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