abhijeet thatte wrote:
Hi, I have a huge dict structure like below: /*{'module':{'reg_dict_0':{'name':'abc','reg_addr':'2004'},'reg_dict_1':{'name':'xyz','reg_addr':'2002'},'reg_dict_2':{'name':'pqr','reg_addr':'2008'}}*/Module dict and reg_dicts contain many elements than shown. I want to sort this 'module' dictionary as per 'reg_addr' element in every 'reg_dict'. There is no relation between 'reg_dict' suffix and address. So, reg_dict_0 can contain reg_address = 2000/72 (any number) I do not want output in a list format as the actual dict size is huge which I want to use based on key value pair.So, I want output as : /*{'module':{'reg_dict_1':{'name':'xyz','reg_addr':'2002'},'reg_dict_0':{'name':'abc','reg_addr':'2004'},'reg_dict_2':{'name':'pqr','reg_addr':'2008'}}*/ /* */Is it possible to sort the things? What I guess is Python stores dicts in a tree like structure but I am forcing it to store the way I want. Is it possible to do something like that.
Python dicts are implemented as hash tables, not trees, for speed, and they are unordered. If the order matters then you should use an ordered dict instead. You should be able to find an implementation of one. -- http://mail.python.org/mailman/listinfo/python-list
