blur959 wrote:
On Aug 13, 6:09 pm, Peter Otten <__pete...@web.de> wrote:
blur959 wrote:
Hi, I tried that, but it doesn't seem to work. My file directory has
many different files extensions, and I want it to return me a number
based on the number of files with similar files extensions. But when I
tried running it, I get many weird numbers. Below is my code i had so
far and the result.
Use glob.glob() instead of os.listdir() if you are only interested in files
with a specific extension:
import glob
len(glob.glob("*.py"))
42
Peter
Hi, I want to make it such that the user inputs a file extension and
it prints the number of similar file extensions out.
I tried doing this:
directory =aw_input("input file directory")
ext =aw_input("input file ext")
file_list =en(glob.glob(ext))
print file_list
And my result was this:
0
which it is suppose to be 11
May I know why? And how do I specify which directory it is searching
the files extension from? I want the user to specify a directory and
it searches the particular directory for the particular file
extensions and prints the number out.
Hope you guys could help.
Thanks
Glob doesn't do much useful unless there's a wildcard. And as you point
out, it also needs the directory. You want to pass it something like
mydirect/*.txt
In your case, you might construct that with something like
os.path.join(directory, "*." + ext)
DaveA
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