As others have said, it's not a matter of precendence. Using the
compiler module
you can see how python actually parses this:
3 > (0 is True)
Compare(Const(3), [('>', Compare(Const(0), [('is', Name('True'))]))])
No great surprise there.
3 > 0 is True
Compare(Const(3), [('>', Const(0)), ('is', Name('True'))])
As you can see, it's not the same. Two comparisons are being done "at
once", not
one comparison on the result of another.
Hope this helps
On 15/09/10 13:34, Yingjie Lan wrote:
Hi,
I am not sure how to interprete this, in the interactive mode:
3>0 is True
False
(3>0) is True
True
3> (0 is True)
True
Why did I get the first 'False'? I'm a little confused.
Thanks in advance for anybody who shed some light on this.
YL
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