On 9/21/10 10:03 PM, gburde...@gmail.com wrote:
Given
m=numpy.array([[1, 2, 3]])
I want to obtain
array([[1, 1, 1, 1, 2, 2, 2, 2, 3, 3, 3, 3]])
One way I've found to do this is:
numpy.reshape(numpy.tile(m,(4,1)),(12,1),'f').T
Another way is:
numpy.reshape(numpy.tile(m,(4,1)).flatten(1),(1,12))
Is there a simpler way to do this, without having to go jump through
so many hoops?
Peter Otten gave you the correct answer. If you have more numpy questions, you
should ask on the numpy mailing list:
http://www.scipy.org/Mailing_Lists
--
Robert Kern
"I have come to believe that the whole world is an enigma, a harmless enigma
that is made terrible by our own mad attempt to interpret it as though it had
an underlying truth."
-- Umberto Eco
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