Hi, I played with an example related to namespaces/scoping. The result is a little confusing:
>>> a=1 >>> def f(): a = a + 1 return a >>> f() I suppose I will get 2 ( 'a' is redefined as a local variable, whose value is obtained by the value of the global variable 'a' plus 1). But this is what I got: >>> a=1 >>> def f(): a = a + 1 return a >>> f() Traceback (most recent call last): File "<pyshell#39>", line 1, in <module> f() File "<pyshell#38>", line 2, in f a = a + 1 UnboundLocalError: local variable 'a' referenced before assignment I'm not sure how to explain this? Thanks! Yingjie -- http://mail.python.org/mailman/listinfo/python-list