[EMAIL PROTECTED] wrote:
> What is the fastest way to code this particular block of code below..
> I used numeric for this currently and I thought it should be really
> fast..
> But, for large sets of data (bx and vbox) it takes a long time and I
> would like to improve.
>
> vbox = array(m) (size: 1000x1000 approx)
> for b in bx:
> vbox[ b[1], b[0]:b[2] ] = 0
> vbox[ b[3], b[0]:b[2] ] = 0
> vbox[ b[1]:b[3], b[0] ] = 0
> vbox[ b[1]:b[3], b[2] ] = 0
>
> and vbox is a 2D array
> where bx is of form [( int,int,int,int),(........) ]
You can try
for b0, b1, b2, b3 in bx:
vbox[b1:b3, b0:b2+1:b2-b0] = 0
vbox[b1:b3+1:b3-b1, b0:b2] = 0
By the way, the bottom/right cell of your box remains nonzero. Is that
intentional?
Peter
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