On 11/08/10 18:34, Seebs wrote:
On 2010-11-09, Ben Finney<ben+pyt...@benfinney.id.au> wrote:
' '.join(x for x in target_cflags.split() if re.match('^-[DIiU]', x))
Ahh, handy.
...
The latter works only in Python with set literals (Python
2.7 or later).
I think we're stuck with backwards compatibility at least as
far as 2.4.
No, I'm not kidding. *sigh*
I feel your pain :) At least be glad you don't have to go back
to 2.3 where Ben's suggested generator-syntax isn't available.
The regex is less clear for the purpose than I'd prefer. For a simple
???is it a member of this small set???, I'd find it more readable to use a
simple list of the actual strings::
' '.join(
x for x in target_cflags.split()
if x in ['-D', '-I', '-i', '-U'])
The regex is intentionally not anchored with a $, because I'm looking
for "starts with", not "is".
I suppose you could do
' '.join(
x for x in target_cflags.split()
if x[:2] in ['-D', '-I', '-i', '-U']
)
or
' '.join(
x for x in target_cflags.split()
if x.startswith(('-D', '-I', '-i', '-U'))
)
or even
' '.join(
x for x in target_cflags.split()
if x[:1] == '-' and x[1:2] in 'DIiU'
)
-tkc
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