On 1/2/2011 6:18 AM, Octavian Rasnita wrote:
Hi,If I want to create a dictionary from a list, is there a better way than the long line below? l = [1, 2, 3, 4, 5, 6, 7, 'a', 8, 'b'] d = dict(zip([l[x] for x in range(len(l)) if x %2 == 0], [l[x] for x in range(len(l)) if x %2 == 1]))
d = dict(zip(l[0::2], l[1::2])) Or, using the "grouper" function recipe from the itertools documentation: d = dict(grouper(2, l)) Cheers, Ian -- http://mail.python.org/mailman/listinfo/python-list
