An adaptation to Hrvoje Niksic's recipe Use a dictionary comprehention instead of a list comprehension or function call:
lyst = [1, 2, 3, 4, 5, 6, 7, 'a', 8, 'b']
it = iter( lyst )
dyct = {i:it.next() for i in it} # I'm using {} and not [] for those
with tiny fonts.
#print dyct
{8: 'b', 1: 2, 3: 4, 5: 6, 7: 'a'}
Of course check for an "even" number of elements to the original list
to avoid exceptions or dropping the last element on traps.
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