On 1/8/2011 11:10 PM, aregee wrote:
pie.py:3: Deprecation Warning: integer argument expected, got float
for b in range(0,(x**0.5)/2):
I expect you want range(0, int((x / 2) ** 0.5) + 1), no?
for b in range(0,(x**0.5)/2):
a = (x-(b**2))**0.5
try:
a = int(a)
except:
print("not an integer")
exit(1)
Your indentation is confusing. Is the try-except contained inside the
for loop or not?
And what are you actually trying to test for here? The assignment here
of "a = int(a)" will never throw an exception as long as the loop runs.
count = 0;
count = count + 1;
Again, confusing indentation. Is this supposed to be part of the except
block? And what is the purpose of incrementing count if you're going to
set it to 0 immediately before? You might as well just write "count = 1"
if (x == a**2 + b**2):
print "double square"
This also appears to be outside of the loop.
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