On Feb 11, 9:10 am, Robert Kern <robert.k...@gmail.com> wrote:
> On 2/11/11 9:06 AM, christian.posta wrote:
>
>
>
> > I searched quickly to see whether this may have been discussed before,
> > but it's possible my search criteria was not refined enough to get any
> > hits. Forgive me if this is a silly question..
>
> > I was reading some Python code from a third-party app for the django
> > project... i saw this in the code and I wasn't certain what it means,
> > nor could I find anything helpful from google.
>
> > Within the __call__ function for a class, I saw a method of that class
> > referred to like this:
>
> > *self.<method_name_here>()
>
> > The brackets indicate the method name.
> > What does the *self refer to??
> > Does it somehow indicate the scope of the 'self' variable?
>
> Can you show the whole statement? Most likely, this was embedded in some other
> call, e.g.:
>
> foo(*self.method())
>
> If this is the case, the * does not bind to "self"; it binds to all of
> (self.method()), i.e.:
>
> foo(*(self.method()))
>
> This is just the foo(*args) syntax that unpacks a tuple into individual
> arguments to pass to foo().
>
> http://docs.python.org/tutorial/controlflow.html#unpacking-argument-l...
>
> --
> Robert Kern
>
> "I have come to believe that the whole world is an enigma, a harmless enigma
> that is made terrible by our own mad attempt to interpret it as though it
> had
> an underlying truth."
> -- Umberto Eco
Yep, you are correct!
It is indeed part of a larger statement. Sorry for the confusion.
Here is the entire snippet:
def get_urls(self):
# In Django 1.1 and later you can hook this in to your urlconf
from django.conf.urls.defaults import patterns
return patterns('', *self.get_urlpatterns())
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