Le 10/04/2011 01:22, Robert Kern a écrit :
No one is saying that every instance of "foo([arg])" in the docs means that the given argument is named such that it is available for keyword arguments. What people are saying is that for bool(), *that happens to be the case*.
what a piece of luck! ;) -- http://mail.python.org/mailman/listinfo/python-list
