Ian Kelly wrote:
On Tue, May 17, 2011 at 2:20 PM, Ethan Furman <et...@stoneleaf.us> wrote:
The big question, though, is would you do it this way:
some_var = bytes(23).replace(b'\x00', b'a')
or this way?
some_var = bytes(b'a' * 23)
Actually, I would just do it this way:
some_var = b'a' * 23
That's already a bytes object. Passing it into the constructor is redundant.
However, as I just discovered, it works well when dealing with a
bytearray object:
some_var = bytearray(b' ' * size) # want space initialized, not null
~Ethan~
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