On Sun, 12 Jun 2011 19:20:00 +0800, TheSaint wrote:
> Hello
> I wrote a program which was working on python 2.x. I'd like to go for
> newer version but I face the problem on how the emails are parsed. In
> particular I'd like to extract the significant parts of the headers, but
> the query to the servers had turned in to list of bytes. What could be a
> method that will parse and return the headers into ascii if I'll pass
> the headers as bytes. Even I don't know whether I can pass as they
> arrive to the program.
>
> For example if I try:
>
> import poplib.POP3
> _pop= poplib.POP3(srvr)
> _pop.user(args[1])
> _pop.pass_(args[2])
>
> header =_pop.top(nmuid, 0)
>
> This will return a list of bytes string and I don't have idea to process
> them in order to have a dictionary containing 'from', 'to', 'cc', 'bcc',
> 'date', 'subject', 'reply-to', 'message-id' as keys.
To parse emails, you should use the email package. It already handles
bytes and strings.
Other than that, I'm not entirely sure I understand your problem. In
general, if you have some bytes, you can decode it into a string by hand:
>>> header = b'To: python-list@python.org\n'
>>> s = header.decode('ascii')
>>> s
'To: python-list@python.org\n'
If this is not what you mean, perhaps you should give an example of what
header looks like, what you hope to get, and a concrete example of how it
differs in Python 3.
--
Steven
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