Hi, all, This question is in the same context of my two earlier questions. This question was raised by some python beginners, and I would like to check with the list to ensure I provide a correct answer.
Here is a code snippet I used to demonstrate the keyword *property*: class A(object): def __init__(self): self.__not_here = 1 def __get_not_here(self): return self.__not_here def __set_not_here(self, v): print "I am called" self.__not_here = v not_here = property(lambda self: self.__get_not_here(), lambda self, v: self.__set_not_here(v)) # not_here = property(lambda self: self.__not_here, lambda self, v: self.__not_here = v) So the question: is it possible to use lambda expression at all for the setter? (As in the last, commented-out line) Python interpreter will throw an exception right there if I use the last line ('SyntaxError: lambda cannot contain assignment'). I'd use pass a setter method anyway. What is your preferred solution? -- Tony Kong *blog:* www.ahwkong.com /*--*/ Don’t EVER make the mistake that you can design something better than what you get from ruthless massively parallel trial-and-error with a feedback cycle. That’s giving your intelligence _much_ too much credit. - Linus Torvalds
-- http://mail.python.org/mailman/listinfo/python-list