On 07/26/2011 08:42 AM, Sells, Fred wrote:
I'm tring to unzip a buffer that is uploaded to django/python. I can
unzip the file in batch mode just fine, but when I get the buffer I get
a "BadZipfile exception. I wrote this snippet to try to isolate the
issue but I don't understand what's going on. I'm guessing that I'm
losing some header/trailer somewhere?
def unittestZipfile(filename):
buffer = ''
f = open(filename)
for i in range(22):
block = f.read()
if len(block) == 0:
break
else:
buffer += block
print len(buffer)
tmp = open('tmp.zip', 'w')
tmp.write(buffer)
tmp.close()
zf = zipfile.ZipFile('tmp.zip')
print dir(zf)
for name in zf.namelist():
print name
print zf.read(name)
____________________________________________________________
2.6.6 (r266:84297, Aug 24 2010, 18:46:32) [MSC v.1500 32 bit (Intel)]
Traceback (most recent call last):
File
"C:\all\projects\AccMDS30Server\mds30\app\uploaders\xmitzipfile.py",
line 162, in<module>
unittestZipfile('wk1live7.8to7.11.zip')
File
"C:\all\projects\AccMDS30Server\mds30\app\uploaders\xmitzipfile.py",
line 146, in unittestZipfile
print zf.read(name)
File "C:\alltools\python26\lib\zipfile.py", line 837, in read
return self.open(name, "r", pwd).read()
File "C:\alltools\python26\lib\zipfile.py", line 867, in open
raise BadZipfile, "Bad magic number for file header"
zipfile.BadZipfile: Bad magic number for file header
You need to specify the file mode since I'm guessing you use Windows
from the traceback:
f = open(filename, 'rb')
and later:
tmp = open('tmp.zip', 'wb')
--
Bill
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