No. L1, L2 = zip(*L)
2011/8/7 Chris Angelico <ros...@gmail.com> > On Sat, Aug 6, 2011 at 6:07 PM, smith jack <thinke...@gmail.com> wrote: > > if a list L is composed with tuple consists of two elements, that is > > L = [(a1, b1), (a2, b2) ... (an, bn)] > > > > is there any simple way to divide this list into two separate lists , > such that > > L1 = [a1, a2... an] > > L2=[b1,b2 ... bn] > > > > i do not want to use loop, any methods to make this done? > > One easy way is to use list comprehensions. Technically that'll > involve a loop, but the loop is handled efficiently under the hood. > > L1 = [x[0] for x in L] > L2 = [x[1] for x in L] > > Another way would be to construct a dictionary from your list of > tuples and then use the keys() and values() of that dictionary to form > your lists (use collections.OrderedDict if the order matters). But I > think the list comps are the best way. > > ChrisA > -- > http://mail.python.org/mailman/listinfo/python-list >
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