On Sat, Sep 24, 2011 at 11:53 PM, Steven D'Aprano
<steve+comp.lang.pyt...@pearwood.info> wrote:
> #1 add multiples of the width to the starting value, 0.
>
> #2 subtract multiples of width from the ending value, 2.1.

#3, go half and half - generate the lower half by adding to the lower
bound, and the upper half by subtracting from the upper bound. Not
sure if it'll help or not but it might be worth a shot.

ChrisA
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