On 15/12/2011 16:36, noydb wrote:
I want to test for equality between two lists. For example, if I have
two lists that are equal in content but not in order, I want a return
of 'equal' -- dont care if they are not in the same order. In order
to get that equality, would I have to sort both lists regardless? if
yes, how (having issues with list.sort)?
Another way i tried, that I think is kind-of roundabout is like
x = [2, 5, 1, 88, 9]
y = [5, 2, 9, 1, 88]
inBoth = list(set(x)& set(y))
and then test that list.count is equal between inBoth and x and/or y.
Any better suggestions?
Thanks for any help!
You could count the number of times each item occurs using the Counter
class in the collections module:
>>> x = [2, 5, 1, 88, 9]
>>> y = [5, 2, 9, 1, 88]
>>> from collections import Counter
>>> cx = Counter(x)
>>> cy = Counter(y)
>>> cx
Counter({88: 1, 1: 1, 2: 1, 5: 1, 9: 1})
>>> cx == cy
True
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