On Thu, 9 Feb 2012 17:43:58 -0800 Chris Rebert <c...@rebertia.com> wrote:
> On Thu, Feb 9, 2012 at 5:23 PM, noydb <jenn.du...@gmail.com> wrote: > > hmmm, okay. > > > > So how would you round UP always? Say the number is 3219, so you > > want 3300 returned. > > http://stackoverflow.com/questions/17944/how-to-round-up-the-result-of-integer-division/96921 > > Thus: (3219 + 99) // 100 > > Slight tangent: Beware negative numbers when using // or %. This trick work always (even if the entry is a float): -(-a//100)*100 >>> -(-3219//100)*100 3300 >>> -(-3200.1//100)*100 3300.0 -- http://mail.python.org/mailman/listinfo/python-list
