On 4/13/2012 17:58, Alexander Blinne wrote:
Am 12.04.2012 18:38, schrieb Kiuhnm:
Almost. Since d.values() = [[1,2], [1,2,3], [1,2,3,4]], you need to use
list(zip(*d.values()))
which is equivalent to
list(zip([1,2], [1,2,3], [1,2,3,4]))
Kiuhnm
While this accidently works in this case, let me remind you that
d.values() does not return the elements of the d in any specific order.
The OP said nothing about ordering.
The fact that the keys are ordered might be accidental :)
(It is a non-random but implementation-specific order, see
<http://docs.python.org/library/stdtypes.html#dict.items>.) Thus if you
need the correct order (as suggested by the dict keys) an explicit
sorting step is required, for example
zip(*[x[1] for x in sorted(d.items(), key=lambda y: y[0])])
Or
zip(*[d[k] for k in sorted(d.keys())])
Kiuhnm
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