FSH <lee.joos...@gmail.com> writes: > I have a simple question. I wish to generate an array of file > pointers.
Welcome to Python. By your description, I think you want a different type: not an array, but a list. I recommend you become familiar with Python's data model <URL:http://docs.python.org/reference/datamodel.html>. > I wish to generate fine pointer array so that I can read the files at > the same time. I don't know about reading the files *at the same time*. If you mean you want to have multiple files open simultaneously and read from any of them arbitrarily, you don't need any particular container type; you just need to have references to those open file objects. Any references will do for that; you don't need pointers in Python. > for index in range(N): > fid[index] = open('data%d.txt' % index,'r') Python has iterable types built in, so you rarely need to maintain an index yourself. Further, Python has “list comprehension”, allowing you to define a list in a single statement by describing how each element is created:: fid = [open('data%d.txt' % count, 'r') for count in range(N)] To learn about this and other useful topics, you should work through Python's tutorial <URL:http://docs.python.org/tutorial/> from start to finish, doing each exercise until you understand the concept being explained. -- \ “We have to go forth and crush every world view that doesn't | `\ believe in tolerance and free speech.” —David Brin | _o__) | Ben Finney -- http://mail.python.org/mailman/listinfo/python-list