On Saturday, September 29, 2012 9:46:22 PM UTC+8, Ramchandra Apte wrote: > On Thursday, 27 September 2012 04:14:42 UTC+5:30, Tim Chase wrote: > > > On 09/26/12 17:28, 88888 Dihedral wrote: > > > > > > > 88888 Dihedral於 2012年9月27日星期四UTC+8上午6時07分35秒寫道: > > > > > > >>>> In these conditions, how to make this list [[0,0,0],[0,0,0]] with "*" > > > > > > >>>> without this behavior? > > > > > > >>> >>> a = [[0]*3 for i in xrange(2)] > > > > > > >>> >>> a[0][0]=2 > > > > > > >>> >>> a > > > > > > >>> [[2, 0, 0], [0, 0, 0]] > > > > > > > > > > > > > > def zeros(m,n): > > > > > > > a=[] > > > > > > > for i in xrange(m): > > > > > > > a.append([0]*n) > > > > > > > return a > > > > > > > > > > > > > > If one wants to tranlate to C, this is the style. > > > > > > > > > > > > But this is Python, so why the heck would anybody want to emulate > > > > > > *C* style? It could also be written in an assembly-language style, > > > > > > COBOL style, or a Fortran style...none of which are particularly > > > > > > valuable. > > > > > > > > > > > > Besides, a C-style would allocate a single array of M*N slots and > > > > > > then calculate 2d offsets into that single array. :-P > > > > > > > > > > > > -tkc > > > > 88888 Dihedral is a bot.
Don't you get it why I avoided the lambda one liner as a functon. I prefer the def way with a name chosen. -- http://mail.python.org/mailman/listinfo/python-list