On 2012-10-07 20:30, subhabangal...@gmail.com wrote:
Dear Group,
Suppose I have a string as,
"Project Gutenberg has 36000 free ebooks for Kindle Android iPad iPhone."
I am terming it as,
str1= "Project Gutenberg has 36000 free ebooks for Kindle Android iPad iPhone."
I am working now with a split function,
str_words=str1.split()
so, I would get the result as,
['Project', 'Gutenberg', 'has', '36000', 'free', 'ebooks', 'for', 'Kindle',
'Android', 'iPad', 'iPhone.']
But I am looking for,
['Project Gutenberg', 'has 36000', 'free ebooks', 'for Kindle', 'Android iPad',
'iPhone']
This can be done if we assign the string as,
str1= "Project Gutenberg, has 36000, free ebooks, for Kindle, Android iPad,
iPhone,"
and then assign the split statement as,
str1_word=str1.split(",")
would produce,
['Project Gutenberg', ' has 36000', ' free ebooks', ' for Kindle', ' Android
iPad', ' iPhone', '']
It can also be done like this:
>>> str1 = "Project Gutenberg has 36000 free ebooks for Kindle Android
iPad iPhone."
>>> # Splitting into words:
>>> s = str1.split()
>>> s
['Project', 'Gutenberg', 'has', '36000', 'free', 'ebooks', 'for',
'Kindle', 'Android', 'iPad', 'iPhone.']
>>> # Using slicing with a stride of 2 gives:
>>> s[0 : : 2]
['Project', 'has', 'free', 'for', 'Android', 'iPhone.']
>>> # Similarly for the other words gives:
>>> s[1 : : 2]
['Gutenberg', '36000', 'ebooks', 'Kindle', 'iPad']
>>> # Combining them in pairs, and adding an extra empty string in case
there's an odd number of words:
>>> [(x + ' ' + y).rstrip() for x, y in zip(s[0 : : 2], s[1 : : 2] + [''])]
['Project Gutenberg', 'has 36000', 'free ebooks', 'for Kindle', 'Android
iPad', 'iPhone.']
My objective generally is achieved, but I want to convert each group here in
tuple so that it can be embedded, like,
[(Project Gutenberg), (has 36000), (free ebooks), (for Kindle), ( Android
iPad), (iPhone), '']
as I see if I assign it as
for i in str1_word:
print i
ti=tuple(i)
print ti
I am not getting the desired result.
If I work again from tuple point, I get it as,
tup1=('Project Gutenberg')
tup2=('has 36000')
tup3=('free ebooks')
tup4=('for Kindle')
tup5=('Android iPad')
tup6=tup1+tup2+tup3+tup4+tup5
print tup6
Project Gutenberghas 36000free ebooksfor KindleAndroid iPad
It's the comma that makes the tuple, not the parentheses, except for the
empty tuple which is just empty parentheses, i.e. ().
Then how may I achieve it? If any one of the learned members can kindly guide
me.
>>> [((x + ' ' + y).rstrip(), ) for x, y in zip(s[0 : : 2], s[1 : : 2]
+ [''])]
[('Project Gutenberg',), ('has 36000',), ('free ebooks',), ('for
Kindle',), ('Android iPad',), ('iPhone.',)]
Is this what you want?
If you want it to be a list of pairs of words, then:
>>> [(x, y) for x, y in zip(s[0 : : 2], s[1 : : 2] + [''])]
[('Project', 'Gutenberg'), ('has', '36000'), ('free', 'ebooks'), ('for',
'Kindle'), ('Android', 'iPad'), ('iPhone.', '')]
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