OK, one more self-reply. :-)
I found http://bugs.python.org/issue5380 which seems to be relevant.
Sounds like the OS is returning an error, and that's naturally being
propagated through Python. And further testing reveals the problem only
surfaces when the child actually exits -- if the child writes data to
the pipe and is more enthusiastic about living, then the parent can read
it successfully. While it'd be nice if my example worked, for my actual
purpose I think that's good enough (I just won't be able to test *quite*
as easily for a while).
I am still curious if anyone know why it worked in 2 though.
Evan
On 10/23/2012 10:03 PM, Evan Driscoll wrote:
Oh, and a little more information:
The log.txt file I create has the message that it's "about to execlp",
and the exec() *does* actually happen -- the IOError is raised after
the child process quits.
Evan
On 10/23/2012 09:59 PM, Evan Driscoll wrote:
I have the following program. Everything is sunshine and rainbows
when I run in in Python 2, but when I run it under Python 3 I get an
IOError. 2to3 only reports one dumb suggestion re. a print call
(which I can get rid of by importing __future__'s print_function, and
then it just suggests removing that import).
Can anyone shed any light? I am on Ubuntu Linux with Python 2.7.3 and
3.2.3.
(Just for the record, I figured out that it ran under Python 2 by
accident as I was reducing it for a "why doesn't this run?" email.
:-) I'm not super-familiar with Py3 as I've mostly only worked with 2.)
I'm not 100% sure how this will come through, so I've also put it at
http://pastebin.com/60wjXSF3.
Evan
import sys
import pty
import os
def get_text(filename):
try:
( child_pid, fd ) = pty.fork() # OK
except OSError as e:
print(str(e))
sys.exit(1)
if child_pid == 0:
try:
with open("log.txt", "w") as f:
f.write("about to execlp")
os.execlp("cat", "cat", filename)
except:
with open("log.txt", "w") as f:
f.write("could not spawn process")
print("Could not spawn")
sys.exit(1)
child_pty = os.fdopen(fd)
return child_pty.read()
if __name__ == "__main__":
print(get_text("my-pty-test.py"))
The read error I get is
Traceback (most recent call last):
File "my-pty-test.py", line 28, in <module>
print(get_text("my-pty-test.py"))
File "my-pty-test.py", line 24, in get_text
return child_pty.read()
IOError: [Errno 5] Input/output error
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