On Sat, Dec 29, 2012 at 3:09 PM, Mitya Sirenef <msire...@lightbird.net
<mailto:msire...@lightbird.net>> wrote:
On 12/29/2012 03:01 PM, Mitya Sirenef wrote:
On 12/29/2012 02:48 PM, Quint Rankid wrote:
>> Newbie question. I've googled a little and haven't found the
answer.
>>
>> Given a list like:
>> w = [1, 2, 3, 1, 2, 4, 4, 5, 6, 1]
>> I would like to be able to do the following as a dict
comprehension.
>> a = {}
>> for x in w:
>> a[x] = a.get(x,0) + 1
>> results in a having the value:
>> {1: 3, 2: 2, 3: 1, 4: 2, 5: 1, 6: 1}
>>
>> I've tried a few things
>> eg
>> a1 = {x:self.get(x,0)+1 for x in w}
>> results in error messages.
>>
>> And
>> a2 = {x:a2.get(x,0)+1 for x in w}
>> also results in error messages.
>>
>> Trying to set a variable to a dict before doing the comprehension
>> a3 = {}
>> a3 = {x:a3.get(x,0)+1 for x in w}
>> gets this result, which isn't what I wanted.
>> {1: 1, 2: 1, 3: 1, 4: 1, 5: 1, 6: 1}
>>
>> I'm not sure that it's possible to do this, and if not, perhaps the
>> most obvious question is what instance does the get method bind to?
>>
>> TIA
>
> Will this do?:
>
> >>> w = [1, 2, 3, 1, 2, 4, 4, 5, 6, 1]
> >>> {x: w.count(x) for x in w}
> {1: 3, 2: 2, 3: 1, 4: 2, 5: 1, 6: 1}
>
>
> - mitya
>
I should probably add that this might be inefficient for large
lists as
it repeats count for each item. If you need it for large lists,
profile
against the 'for loop' version and decide if performance is good
enough
for you, for small lists it's a nice and compact solution.
In a more general case, you can't refer to the list/dict/etc
comprehension as it's being constructed, that's just not a design goal
of comprehensions.
Would this help:
>>> w = [1,2,3,1,2,4,4,5,6,1]
>>> s = set(w)
>>> s
set([1, 2, 3, 4, 5, 6])
>>> {x:w.count(x) for x in s}
{1: 3, 2: 2, 3: 1, 4: 2, 5: 1, 6: 1}
>>>
