Am 11.01.2013 17:33 schrieb kwakukwat...@gmail.com:

def factorial(n):
     if n<2:
              return 1
     f = 1
     while n>= 2:
         f *= n
         f -= 1
     return f



please it works.

I doubt this.

If you give n = 4, you run into an endless loop.


but don’t get why the return 1 and the code below.

The "if n < 2: return 1" serves to shorten the calculation process below. It is redundant, as you have a "f = 1" and a "return f" for n < 2.

The code below first sets f, which holds the result, to 1 and then multiplies it by n in each step. As the loop should contain a 'n -= 1', n decreases by 1 every step, turning it into f = n * (n-1) * (n-2) * ... * 2 and then, as n is not >= 2 any longer, stops the loop, returning f.

HTH,

Thomas
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