On 21/01/2013 11:25, Tom Borkin wrote:
> Hi;
> I have this code:
>  
> #!/Python27/python
> import os, subprocess, sys
> lyrics_path = "/Users/Tom/Documents/lyrics"
> os.chdir(lyrics_path)
>  
> songs = ['livin-la-vida-loca', 'whos-that-lady']
> for song in songs:
>   subprocess.call(['notepad.exe', '%s.txt' % song])
> my_songs_path = "aa english lyrics"
> os.chdir(my_songs_path)
> for song in my_songs:
>   subprocess.call(['notepad.exe', '%s.txt' % song])
>   print song
>  
> It opens the first song and hangs on subsequent songs. It doesn't open
> the next song or execute the print until I have closed the first one. I
> want it to open all in the list, one after another, so I have all those
> songs available. Please advise.

subprocess.call is a convenience for starting a process and waiting for
it to finish. If you want to start a process and carry on, use
subprocess.Popen directly (same params)

TJG
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