On 1/29/2013 1:49 PM, Alok Singhal wrote:
On Tue, 29 Jan 2013 00:41:54 -0800, C. Ng wrote:
Is there a numpy operation that does the following to the array?
1 2 ==> 4 3
3 4 2 1
Thanks in advance.
How about:
import numpy as np
a = np.array([[1,2],[3,4]])
a
array([[1, 2], [3, 4]])
a[::-1, ::-1]
array([[4, 3], [2, 1]])
Nice. The regular Python equivalent is
a = [[1,2],[3,4]]
print([row[::-1] for row in a[::-1]])
>>>
[[4, 3], [2, 1]]
The second slice can be replaced with reversed(a), which returns an
iterator, to get
[row[::-1] for row in reversed(a)]
The first slice would have to be list(reversed(a)) to get the same result.
--
Terry Jan Reedy
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