How to reverse the two loops? On Tuesday, February 5, 2013 2:43:47 PM UTC-5, Dave Angel wrote: > On 02/05/2013 02:20 PM, maiden129 wrote: > > > On Tuesday, February 5, 2013 1:56:55 PM UTC-5, marduk wrote: > > >> On Tue, Feb 5, 2013, at 01:38 PM, maiden129 wrote: > > >> > > <Snipping double-spaced googlegroups trash> > > > > > > when I removed "s.remove(i), it starts to repeat the number of occurrences > > too > > > > > > many times like this: > > > > > > 2 occurs 3 times. > > > 2 occurs 3 times. > > > 3 occurs 3 times. > > > 3 occurs 3 times. > > > 2 occurs 3 times. > > > 2 occurs 3 times. > > > 5 occurs 1 time. > > > 3 occurs 3 times. > > > 3 occurs 3 times. > > > 4 occurs 1 time. > > > 3 occurs 3 times. > > > 3 occurs 3 times. > > > 1 occurs 1 time. > > > 2 occurs 3 times. > > > 2 occurs 3 times. > > > > > > How can I stop this? > > > > > > > As MRAB pointed out, don't delete items from a list you're iterating > > over. It can make the iterator go nuts. He suggests the collections > > module. > > > > But if you want to do it by hand, one approach is to reverse the two > > loops. Iterate over the characters in CheckS list, examining the entire > > s list for each one and figuring out how many times the character occurs. > > > > Another approach is to build a dict, or a defaultdict, to keep counts > > for each of the characters in CheckS. > > > > -- > > DaveA
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