Τη Παρασκευή, 22 Φεβρουαρίου 2013 3:35:31 μ.μ. UTC+2, ο χρήστης Lele Gaifax
έγραψε:
> Ferrous Cranus <nikos.gr...@gmail.com> writes:
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>
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> > Let me ask it like this:
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> > How can i avoid using try: except: for checkign the date but instead check
> > it with an if statement:
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>
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> Let me answer this way: you can't, without resorting to the simple
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> helper functions I wrote in my previous message.
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> Why do you dislike that solution?
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> ciao, lele.
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> --
>
> nickname: Lele Gaifax | Quando vivrò di quello che ho pensato ieri
>
> real: Emanuele Gaifas | comincerò ad aver paura di chi mi copia.
>
> l...@metapensiero.it | -- Fortunato Depero, 1929.
ok, i'll just use the try: except: i was just thinking putting them all in the
same if() statemt but apparently it cant be done.
Actually it can, but instead of try: i have to create a function:
def is_sane_date(date):
parts = [int(part) for part in date.split() if part.isdigit()]
if len(parts) == 3 and \
1 <= parts[0] <= 31 and \
1 <= parts[1] <= 12 and \
1900 <= parts[2] <= 2100:
return True
return False
if is_sane_date(date):
# ...
but the try: solution is much more less hassle.
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